What is the answer to log_{2}(x-4)+log_{2}(x+3)=3 ?

The answer to log_{2}(x-4)+log_{2}(x+3)=3 is x=5

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log_{2}(x-4)+log_{2}(x+3)=3

lo g_{2} (x - 4) + lo g_{2} (x + 3) = 3

x = 5

Solution steps

lo g_{2} (x - 4) + lo g_{2} (x + 3) = 3

Apply log rules

(x - 4) (x + 3) = 8

Solve

(x - 4) (x + 3) = 8 : x = 5, x = - 4

x = 5, x = - 4

Verify Solutions:

x = 5

True

, x = - 4

False

The solution is

x = 5

lo g_{3} (x^{2} - 6 x + 6) = 0

2 ln (x) = lo g_{e^{3}} (216)

lo g_{3} (x) = lo g_{9} (21)

ln (x + 5) = 1 + ln (x)

3 lo g_{3} (x - 2) = 5

What is the answer to log_{2}(x-4)+log_{2}(x+3)=3 ?
The answer to log_{2}(x-4)+log_{2}(x+3)=3 is x=5
Solve for x: log_{2}(x-4)+log_{2}(x+3)=3
The solution is x=5