What is the answer to log_{2}(x^2-3x)=2 ?

The answer to log_{2}(x^2-3x)=2 is x=4,x=-1

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log_{2}(x^2-3x)=2

lo g_{2} (x^{2} - 3 x) = 2

x = 4, x = - 1

Solution steps

lo g_{2} (x^{2} - 3 x) = 2

Apply log rules

x^{2} - 3 x = 4

Solve

x^{2} - 3 x = 4 : x = 4, x = - 1

x = 4, x = - 1

lo g_{10} (x + 3) - 2 lo g_{10} (x) = 1

lo g_{3} (7 x + 8) = lo g_{3} (7 x + 2)

ln (2 x + 1) = 2 ln (x) + ln (5)

4 ln (3 x - 4) + 16 = 24

lo g_{3} (x) = 3 - lo g_{3} (x + 6)

What is the answer to log_{2}(x^2-3x)=2 ?
The answer to log_{2}(x^2-3x)=2 is x=4,x=-1
Solve for x: log_{2}(x^2-3x)=2
The solution is x=4,x=-1