What is the answer to log_{2}(-5x)+log_{2}(9)=2 ?

The answer to log_{2}(-5x)+log_{2}(9)=2 is x=-4/45

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log_{2}(-5x)+log_{2}(9)=2

lo g_{2} (- 5 x) + lo g_{2} (9) = 2

x = - \frac{4}{45}

Decimal Notation

x = - 0.08888 \dots

Solution steps

lo g_{2} (- 5 x) + lo g_{2} (9) = 2

Move

lo g_{2} (9)

to the right side

lo g_{2} (- 5 x) = 2 - lo g_{2} (9)

Apply log rules

- 5 x = \frac{4}{9}

Solve

- 5 x = \frac{4}{9} : x = - \frac{4}{45}

x = - \frac{4}{45}

Verify Solutions:

x = - \frac{4}{45}

True

The solution is

x = - \frac{4}{45}

lo g_{6} (x^{3}) = 3

y, ln (y) = 3 x

lo g_{10} (4 x) = \frac{- 3}{2}

lo g_{10} (2 x + 1) = lo g_{10} (5)

lo g_{10} (x^{2} + 15 x) = 2

What is the answer to log_{2}(-5x)+log_{2}(9)=2 ?
The answer to log_{2}(-5x)+log_{2}(9)=2 is x=-4/45
Solve for x: log_{2}(-5x)+log_{2}(9)=2
The solution is x=-4/45