What is the answer to log_{6}(x)=log_{3}(4x) ?

The answer to log_{6}(x)=log_{3}(4x) is x=6^{(2log_{6}(2))/(log_{6)(3)-1}}

Solve for x: log_{6}(x)=log_{3}(4x)

The solution is x=6^{(2log_{6}(2))/(log_{6)(3)-1}}

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lo g_{6} (x) = lo g_{3} (4 x)

x = 6^{\frac{2 l o g _{6} ( 2 )}{l o g _{6} ( 3 ) - 1}}

Solution steps

lo g_{6} (x) = lo g_{3} (4 x)

Apply log rules

x = 6^{\frac{2 l o g _{6} ( 2 )}{l o g _{6} ( 3 ) - 1}}

Verify Solutions:

x = 6^{\frac{2 l o g _{6} ( 2 )}{l o g _{6} ( 3 ) - 1}}

True

The solution is

x = 6^{\frac{2 l o g _{6} ( 2 )}{l o g _{6} ( 3 ) - 1}}

ln (x + 10) + ln (x - 2) = 2 ln (x)

3 = lo g_{4} (x)

lo g_{2} (y) + lo g_{2} (y + 1) = 1

lo g_{10} (x) = - 4.6

lo g_{10} (x - 2) - lo g_{10} (x) = 0

What is the answer to log_{6}(x)=log_{3}(4x) ?
The answer to log_{6}(x)=log_{3}(4x) is x=6^{(2log_{6}(2))/(log_{6)(3)-1}}
Solve for x: log_{6}(x)=log_{3}(4x)
The solution is x=6^{(2log_{6}(2))/(log_{6)(3)-1}}