What is the answer to ln(x+10)+ln(x-2)=2ln(x) ?

The answer to ln(x+10)+ln(x-2)=2ln(x) is x= 5/2

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ln(x+10)+ln(x-2)=2ln(x)

ln (x + 10) + ln (x - 2) = 2 ln (x)

x = \frac{5}{2}

Solution steps

ln (x + 10) + ln (x - 2) = 2 ln (x)

Apply log rules

(x + 10) (x - 2) = x^{2}

Solve

(x + 10) (x - 2) = x^{2} : x = \frac{5}{2}

x = \frac{5}{2}

Verify Solutions:

x = \frac{5}{2}

True

The solution is

x = \frac{5}{2}

3 = lo g_{4} (x)

lo g_{2} (y) + lo g_{2} (y + 1) = 1

lo g_{10} (x) = - 4.6

lo g_{10} (x - 2) - lo g_{10} (x) = 0

ln (x^{2} + 12 x) = ln (3 x - 18)

What is the answer to ln(x+10)+ln(x-2)=2ln(x) ?
The answer to ln(x+10)+ln(x-2)=2ln(x) is x= 5/2
Solve for x: ln(x+10)+ln(x-2)=2ln(x)
The solution is x= 5/2