What is the answer to log_{10}(x)=-2.5 ?

The answer to log_{10}(x)=-2.5 is x= 1/(10^{2.5)}

Solve for x: log_{10}(x)=-2.5

The solution is x= 1/(10^{2.5)}

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lo g_{10} (x) = - 2.5

x = \frac{1}{1 0 ^{2.5}}

Solution steps

lo g_{10} (x) = - 2.5

Apply log rules

x = \frac{1}{1 0 ^{2.5}}

ln (6) + ln (x^{2}) = ln (2 - x)

ln (x + 2) = 7

2 ln (3 x^{2}) - ln (x) = 4

y, \frac{1}{2} ln (y) = x

lo g_{10} (x) = - 1.2

What is the answer to log_{10}(x)=-2.5 ?
The answer to log_{10}(x)=-2.5 is x= 1/(10^{2.5)}
Solve for x: log_{10}(x)=-2.5
The solution is x= 1/(10^{2.5)}