What is the answer to log_{2}(x+2)+log_{2}(5)=4 ?

The answer to log_{2}(x+2)+log_{2}(5)=4 is x= 6/5

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log_{2}(x+2)+log_{2}(5)=4

lo g_{2} (x + 2) + lo g_{2} (5) = 4

x = \frac{6}{5}

Solution steps

lo g_{2} (x + 2) + lo g_{2} (5) = 4

Move

lo g_{2} (5)

to the right side

lo g_{2} (x + 2) = 4 - lo g_{2} (5)

Apply log rules

x + 2 = \frac{16}{5}

Solve

x + 2 = \frac{16}{5} : x = \frac{6}{5}

x = \frac{6}{5}

Verify Solutions:

x = \frac{6}{5}

True

The solution is

x = \frac{6}{5}

ln (2) + ln (x - 3) = ln (x + 2)

ln (4 x) = 1.4

lo g_{8} (2 x^{2} - 8 x) = 2

lo g_{10} (5 x - 1) = lo g_{10} (9 x)

lo g_{10} (x) = \frac{3}{2}

What is the answer to log_{2}(x+2)+log_{2}(5)=4 ?
The answer to log_{2}(x+2)+log_{2}(5)=4 is x= 6/5
Solve for x: log_{2}(x+2)+log_{2}(5)=4
The solution is x= 6/5