What is the answer to log_{10}(4x+1)=log_{10}(x+2) ?

The answer to log_{10}(4x+1)=log_{10}(x+2) is x= 1/3

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log_{10}(4x+1)=log_{10}(x+2)

lo g_{10} (4 x + 1) = lo g_{10} (x + 2)

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

lo g_{10} (4 x + 1) = lo g_{10} (x + 2)

Apply log rules

4 x + 1 = x + 2

Solve

4 x + 1 = x + 2 : x = \frac{1}{3}

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

lo g_{10} (2 x - 100) = 3

0.69 = ln (y)

lo g_{10} (m) + lo g_{10} (m - 3) = 1

ln (x - 2) + ln (3) = 5

ln (x) + ln (2 x) = - 3

What is the answer to log_{10}(4x+1)=log_{10}(x+2) ?
The answer to log_{10}(4x+1)=log_{10}(x+2) is x= 1/3
Solve for x: log_{10}(4x+1)=log_{10}(x+2)
The solution is x= 1/3