What is the answer to ln(3x+10)-ln(2x)=4 ?

The answer to ln(3x+10)-ln(2x)=4 is x=(10)/(2e^4-3)

Solve for x: ln(3x+10)-ln(2x)=4

The solution is x=(10)/(2e^4-3)

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ln (3 x + 10) - ln (2 x) = 4

x = \frac{10}{2 e ^{4} - 3}

Solution steps

ln (3 x + 10) - ln (2 x) = 4

Add

ln (2 x)

to both sides

ln (3 x + 10) - ln (2 x) + ln (2 x) = 4 + ln (2 x)

Simplify

ln (3 x + 10) = 4 + ln (2 x)

Apply log rules

3 x + 10 = e^{4} \cdot 2 x

Solve

3 x + 10 = e^{4} \cdot 2 x : x = \frac{10}{2 e ^{4} - 3}

x = \frac{10}{2 e ^{4} - 3}

Verify Solutions:

x = \frac{10}{2 e ^{4} - 3}

True

The solution is

x = \frac{10}{2 e ^{4} - 3}

lo g_{2} (x + 5) + lo g_{2} (x - 1) = 4

lo g_{2 x} (4) = 2

lo g_{8} (N) = \frac{1}{3}

2 lo g_{3} (y - 6) - lo g_{3} (y - 4) = 2

5 ln (8 x - 4) + 5 = 25

What is the answer to ln(3x+10)-ln(2x)=4 ?
The answer to ln(3x+10)-ln(2x)=4 is x=(10)/(2e^4-3)
Solve for x: ln(3x+10)-ln(2x)=4
The solution is x=(10)/(2e^4-3)