What is the answer to log_{2}(log_{3}(3x-6))=1 ?

The answer to log_{2}(log_{3}(3x-6))=1 is x=5

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log_{2}(log_{3}(3x-6))=1

lo g_{2} (lo g_{3} (3 x - 6)) = 1

x = 5

Solution steps

lo g_{2} (lo g_{3} (3 x - 6)) = 1

Apply log rules

3 x - 6 = 9

Solve

3 x - 6 = 9 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{b} (8) = 3

2 ln (3 x) = 8

24 \cdot lo g_{10} (2 x) = 60

lo g_{10} (3 x) + lo g_{10} (9 x) = 1

y, ln (y - 38) = 5 t

What is the answer to log_{2}(log_{3}(3x-6))=1 ?
The answer to log_{2}(log_{3}(3x-6))=1 is x=5
Solve for x: log_{2}(log_{3}(3x-6))=1
The solution is x=5