What is the answer to solvefor y,ln(y-38)=5t ?

The answer to solvefor y,ln(y-38)=5t is y=e^{5t}+38

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solvefor y,ln(y-38)=5t

solve for

y, ln (y - 38) = 5 t

y = e^{5 t} + 38

Solution steps

ln (y - 38) = 5 t

Apply log rules

y - 38 = e^{5 t}

Solve

y - 38 = e^{5 t} : y = e^{5 t} + 38

y = e^{5 t} + 38

lo g_{16} (x + 1) = \frac{1}{2}

lo g_{2} (x + 2) = - 4

x, ln (x) = y t + c

lo g_{2} (x) + lo g_{2} (x + 3) = 2

lo g_{5} (a) = 3

What is the answer to solvefor y,ln(y-38)=5t ?
The answer to solvefor y,ln(y-38)=5t is y=e^{5t}+38