What is the answer to log_{10}(3x)+log_{10}(9x)=1 ?

The answer to log_{10}(3x)+log_{10}(9x)=1 is x=10^{(1-3log_{10}(3))/2}

Solve for x: log_{10}(3x)+log_{10}(9x)=1

The solution is x=10^{(1-3log_{10}(3))/2}

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lo g_{10} (3 x) + lo g_{10} (9 x) = 1

x = 1 0^{\frac{1 - 3 l o g _{10} ( 3 )}{2}}

Decimal Notation

x = 0.60858 \dots

Solution steps

lo g_{10} (3 x) + lo g_{10} (9 x) = 1

Apply log rules

x = 1 0^{\frac{1 - 3 l o g _{10} ( 3 )}{2}}

Verify Solutions:

x = 1 0^{\frac{1 - 3 l o g _{10} ( 3 )}{2}}

True

The solution is

x = 1 0^{\frac{1 - 3 l o g _{10} ( 3 )}{2}}

y, ln (y - 38) = 5 t

lo g_{16} (x + 1) = \frac{1}{2}

lo g_{2} (x + 2) = - 4

x, ln (x) = y t + c

lo g_{2} (x) + lo g_{2} (x + 3) = 2

What is the answer to log_{10}(3x)+log_{10}(9x)=1 ?
The answer to log_{10}(3x)+log_{10}(9x)=1 is x=10^{(1-3log_{10}(3))/2}
Solve for x: log_{10}(3x)+log_{10}(9x)=1
The solution is x=10^{(1-3log_{10}(3))/2}