What is the answer to log_{10}(3x)+log_{10}(x)9=3 ?

The answer to log_{10}(3x)+log_{10}(x)9=3 is x=10^{(3-log_{10}(3))/(10)}

Solve for x: log_{10}(3x)+log_{10}(x)9=3

The solution is x=10^{(3-log_{10}(3))/(10)}

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lo g_{10} (3 x) + lo g_{10} (x) 9 = 3

x = 1 0^{\frac{3 - l o g _{10} ( 3 )}{10}}

Solution steps

lo g_{10} (3 x) + lo g_{10} (x) \cdot 9 = 3

Apply log rules

x = 1 0^{\frac{3 - l o g _{10} ( 3 )}{10}}

Verify Solutions:

x = 1 0^{\frac{3 - l o g _{10} ( 3 )}{10}}

True

The solution is

x = 1 0^{\frac{3 - l o g _{10} ( 3 )}{10}}

lo g_{2} (3 x + 1) = lo g_{2} (x + 3)

2 lo g_{10} (x - 1) - lo g_{10} (x) = 0

lo g_{2} (4 x - 1) = 3

x, y = ln (x y)

ln (1 - 2 x) = 0.4

What is the answer to log_{10}(3x)+log_{10}(x)9=3 ?
The answer to log_{10}(3x)+log_{10}(x)9=3 is x=10^{(3-log_{10}(3))/(10)}
Solve for x: log_{10}(3x)+log_{10}(x)9=3
The solution is x=10^{(3-log_{10}(3))/(10)}