What is the answer to log_{10}(81)=4log_{10}(x) ?

The answer to log_{10}(81)=4log_{10}(x) is x=3

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log_{10}(81)=4log_{10}(x)

lo g_{10} (81) = 4 lo g_{10} (x)

x = 3

Solution steps

lo g_{10} (81) = 4 lo g_{10} (x)

Switch sides

4 lo g_{10} (x) = lo g_{10} (81)

Divide both sides by

4

lo g_{10} (x) = \frac{lo g _{10} ( 81 )}{4}

Apply log rules

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

lo g_{10} (1 - k) = - \frac{0.3}{8}

lo g_{b} (3) = 1

lo g_{16} (36) = 1 - lo g_{4} (x)

n - 8 lo g_{10} (n) = 0

x, lo g_{3} (x + 1) = 3

What is the answer to log_{10}(81)=4log_{10}(x) ?
The answer to log_{10}(81)=4log_{10}(x) is x=3
Solve for x: log_{10}(81)=4log_{10}(x)
The solution is x=3