What is the answer to 2+log_{3}(2x+5)-log_{3}(x)=4 ?

The answer to 2+log_{3}(2x+5)-log_{3}(x)=4 is x= 5/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2+log_{3}(2x+5)-log_{3}(x)=4

2 + lo g_{3} (2 x + 5) - lo g_{3} (x) = 4

x = \frac{5}{7}

Decimal Notation

x = 0.71428 \dots

Solution steps

2 + lo g_{3} (2 x + 5) - lo g_{3} (x) = 4

Add

lo g_{3} (x)

to both sides

2 + lo g_{3} (2 x + 5) - lo g_{3} (x) + lo g_{3} (x) = 4 + lo g_{3} (x)

Simplify

2 + lo g_{3} (2 x + 5) = 4 + lo g_{3} (x)

Apply log rules

9 (2 x + 5) = 81 x

Solve

9 (2 x + 5) = 81 x : x = \frac{5}{7}

x = \frac{5}{7}

Verify Solutions:

x = \frac{5}{7}

True

The solution is

x = \frac{5}{7}

lo g_{2} (5 - 2 x) = 3 + lo g_{2} (x + 1)

lo g_{x + 6} (2 x^{2} + 3 x) = 2

lo g_{3} (x) + 2 lo g_{9} (x) = 4

0.53 = ln (y)

\frac{1}{2} = lo g_{x} (10)

What is the answer to 2+log_{3}(2x+5)-log_{3}(x)=4 ?
The answer to 2+log_{3}(2x+5)-log_{3}(x)=4 is x= 5/7
Solve for x: 2+log_{3}(2x+5)-log_{3}(x)=4
The solution is x= 5/7