What is the answer to log_{2}(5-2x)=3+log_{2}(x+1) ?

The answer to log_{2}(5-2x)=3+log_{2}(x+1) is x=-3/10

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log_{2}(5-2x)=3+log_{2}(x+1)

lo g_{2} (5 - 2 x) = 3 + lo g_{2} (x + 1)

x = - \frac{3}{10}

Decimal Notation

x = - 0.3

Solution steps

lo g_{2} (5 - 2 x) = 3 + lo g_{2} (x + 1)

Apply log rules

5 - 2 x = 8 (x + 1)

Solve

5 - 2 x = 8 (x + 1) : x = - \frac{3}{10}

x = - \frac{3}{10}

Verify Solutions:

x = - \frac{3}{10}

True

The solution is

x = - \frac{3}{10}

lo g_{x + 6} (2 x^{2} + 3 x) = 2

lo g_{3} (x) + 2 lo g_{9} (x) = 4

0.53 = ln (y)

\frac{1}{2} = lo g_{x} (10)

x, ln (x) + ln (x + 1) = 0

What is the answer to log_{2}(5-2x)=3+log_{2}(x+1) ?
The answer to log_{2}(5-2x)=3+log_{2}(x+1) is x=-3/10
Solve for x: log_{2}(5-2x)=3+log_{2}(x+1)
The solution is x=-3/10