What is the answer to log_{2}(x-5)+log_{2}(x+5)=5 ?

The answer to log_{2}(x-5)+log_{2}(x+5)=5 is x=sqrt(57)

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log_{2}(x-5)+log_{2}(x+5)=5

lo g_{2} (x - 5) + lo g_{2} (x + 5) = 5

x = 57

Decimal Notation

x = 7.54983 \dots

Solution steps

lo g_{2} (x - 5) + lo g_{2} (x + 5) = 5

Apply log rules

(x - 5) (x + 5) = 32

Solve

(x - 5) (x + 5) = 32 : x = 57, x = - 57

x = 57, x = - 57

Verify Solutions:

x = 57

True

, x = - 57

False

The solution is

x = 57

4 - lo g_{2} (1 - 3 x) = 3

2 x^{2} = \frac{x ^{2}}{ln ( x )}

ln (x^{2}) = 4 ln (x)

lo g_{100} (x) = \frac{3}{2}

0.21 = ln (y)

What is the answer to log_{2}(x-5)+log_{2}(x+5)=5 ?
The answer to log_{2}(x-5)+log_{2}(x+5)=5 is x=sqrt(57)
Solve for x: log_{2}(x-5)+log_{2}(x+5)=5
The solution is x=sqrt(57)