What is the answer to 2log_{2}(x-3)-log_{2}(x+6)=0 ?

The answer to 2log_{2}(x-3)-log_{2}(x+6)=0 is x=(7+sqrt(37))/2

Solve for x: 2log_{2}(x-3)-log_{2}(x+6)=0

The solution is x=(7+sqrt(37))/2

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2 lo g_{2} (x - 3) - lo g_{2} (x + 6) = 0

x = \frac{7 + 37}{2}

Decimal Notation

x = 6.54138 \dots

Solution steps

2 lo g_{2} (x - 3) - lo g_{2} (x + 6) = 0

Apply log rules

(x - 3)^{2} = x + 6

Solve

(x - 3)^{2} = x + 6 : x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

Verify Solutions:

x = \frac{7 + 37}{2}

True

, x = \frac{7 - 37}{2}

False

The solution is

x = \frac{7 + 37}{2}

ln (x + 3) \cdot ln (x - 3) = 0

lo g_{10} (5 x + 3) = lo g_{10} (12)

ln (3 x - 15) = 8

ln (1 - 4 k) = - 6 k

lo g_{10} (x + 8) + lo g_{10} (15) = 2

What is the answer to 2log_{2}(x-3)-log_{2}(x+6)=0 ?
The answer to 2log_{2}(x-3)-log_{2}(x+6)=0 is x=(7+sqrt(37))/2
Solve for x: 2log_{2}(x-3)-log_{2}(x+6)=0
The solution is x=(7+sqrt(37))/2