What is the answer to log_{5}(7x)-2log_{5}(3)=0 ?

The answer to log_{5}(7x)-2log_{5}(3)=0 is x= 9/7

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log_{5}(7x)-2log_{5}(3)=0

lo g_{5} (7 x) - 2 lo g_{5} (3) = 0

x = \frac{9}{7}

Decimal Notation

x = 1.28571 \dots

Solution steps

lo g_{5} (7 x) - 2 lo g_{5} (3) = 0

Move

2 lo g_{5} (3)

to the right side

lo g_{5} (7 x) = 2 lo g_{5} (3)

Apply log rules

7 x = 9

Solve

7 x = 9 : x = \frac{9}{7}

x = \frac{9}{7}

Verify Solutions:

x = \frac{9}{7}

True

The solution is

x = \frac{9}{7}

lo g_{\frac{1}{2}} (x + 8) - 1 = 0

lo g_{4} (y) - lo g_{2} (y) = 12

lo g_{y} (100) = lo g_{10} (y)

\frac{ln ( x + 3 )}{ln ( x + 1 )} = 2

ln (2) + ln (x) = 5

What is the answer to log_{5}(7x)-2log_{5}(3)=0 ?
The answer to log_{5}(7x)-2log_{5}(3)=0 is x= 9/7
Solve for x: log_{5}(7x)-2log_{5}(3)=0
The solution is x= 9/7