What is the answer to log_{2}(6x+3)=1 ?

The answer to log_{2}(6x+3)=1 is x=-1/6

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log_{2}(6x+3)=1

lo g_{2} (6 x + 3) = 1

x = - \frac{1}{6}

Decimal Notation

x = - 0.16666 \dots

Solution steps

lo g_{2} (6 x + 3) = 1

Apply log rules

6 x + 3 = 2

Solve

6 x + 3 = 2 : x = - \frac{1}{6}

x = - \frac{1}{6}

lo g_{10} (x) = 1.62

lo g_{3} (x) lo g_{9} (x) = 1

ln (x) + 2 ln (2) = 2

lo g_{6} (x) + lo g_{6} (x - 16) = 2

ln (x^{2} + x) = 0