What is the answer to log_{10}(sqrt(x))=1.62 ?

The answer to log_{10}(sqrt(x))=1.62 is x=10^{3.24}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(sqrt(x))=1.62

lo g_{10} (x) = 1.62

x = 1 0^{3.24}

Decimal Notation

x = 1737.80082 \dots

Solution steps

lo g_{10} (x) = 1.62

Apply log rules

x = 1 0^{1.62}

Solve

x = 1 0^{1.62} : x = 1 0^{3.24}

x = 1 0^{3.24}

lo g_{3} (x) lo g_{9} (x) = 1

ln (x) + 2 ln (2) = 2

lo g_{6} (x) + lo g_{6} (x - 16) = 2

ln (x^{2} + x) = 0

lo g_{56} (x^{2} - x) = 1

What is the answer to log_{10}(sqrt(x))=1.62 ?
The answer to log_{10}(sqrt(x))=1.62 is x=10^{3.24}
Solve for x: log_{10}(sqrt(x))=1.62
The solution is x=10^{3.24}