What is the answer to ln(x^2+x)=0 ?

The answer to ln(x^2+x)=0 is x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

Solve for x: ln(x^2+x)=0

The solution is x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

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ln (x^{2} + x) = 0

x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

Decimal Notation

x = 0.61803 \dots, x = - 1.61803 \dots

Solution steps

ln (x^{2} + x) = 0

Apply log rules

x^{2} + x = 1

Solve

x^{2} + x = 1 : x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

lo g_{56} (x^{2} - x) = 1

2 lo g_{3} (x) - lo g_{3} (x + 4) = 2

lo g_{10} (x - 3) = 1

0.26 = ln (x)

ln (20 C) = ln (5)

What is the answer to ln(x^2+x)=0 ?
The answer to ln(x^2+x)=0 is x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2
Solve for x: ln(x^2+x)=0
The solution is x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2