What is the answer to log_{2}(x^2+3x)=2 ?

The answer to log_{2}(x^2+3x)=2 is x=1,x=-4

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log_{2}(x^2+3x)=2

lo g_{2} (x^{2} + 3 x) = 2

x = 1, x = - 4

Solution steps

lo g_{2} (x^{2} + 3 x) = 2

Apply log rules

x^{2} + 3 x = 4

Solve

x^{2} + 3 x = 4 : x = 1, x = - 4

x = 1, x = - 4

lo g_{b} (x) = 0.38

x, ln (x) = y^{2} + c

3 ln (x) + 2 = 0

lo g_{2} (x) + 1 - lo g_{2} (x) - 4 = 3

What is the answer to log_{2}(x^2+3x)=2 ?
The answer to log_{2}(x^2+3x)=2 is x=1,x=-4
Solve for x: log_{2}(x^2+3x)=2
The solution is x=1,x=-4