What is the answer to 6.021=20log_{10}(a) ?

The answer to 6.021=20log_{10}(a) is a=10^{0.30105}

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6.021=20log_{10}(a)

6.021 = 20 lo g_{10} (a)

a = 1 0^{0.30105}

Decimal Notation

a = 2.00009 \dots

Solution steps

6.021 = 20 lo g_{10} (a)

Switch sides

20 lo g_{10} (a) = 6.021

Divide both sides by

20

lo g_{10} (a) = 0.30105

Apply log rules

a = 1 0^{0.30105}

Verify Solutions:

a = 1 0^{0.30105}

True

The solution is

a = 1 0^{0.30105}

lo g_{5} (x) - lo g_{25} (x + 6) = 0

lo g_{x} (512) = 9

ln (15) = ln (- n) - n ln (1.1)

lo g_{2} (x + 7) + lo g_{2} (x - 7) = 5

5 ln (3 x - 4) = 30

What is the answer to 6.021=20log_{10}(a) ?
The answer to 6.021=20log_{10}(a) is a=10^{0.30105}
Solve for a: 6.021=20log_{10}(a)
The solution is a=10^{0.30105}