What is the answer to log_{3}(2x)=1-log_{3}(x) ?

The answer to log_{3}(2x)=1-log_{3}(x) is x=3^{(1-log_{3}(2))/2}

Solve for x: log_{3}(2x)=1-log_{3}(x)

The solution is x=3^{(1-log_{3}(2))/2}

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lo g_{3} (2 x) = 1 - lo g_{3} (x)

x = 3^{\frac{1 - l o g _{3} ( 2 )}{2}}

Decimal

x = 1.22474 \dots

Solution steps

lo g_{3} (2 x) = 1 - lo g_{3} (x)

Apply log rules

x = 3^{\frac{1 - l o g _{3} ( 2 )}{2}}

Verify Solutions:

x = 3^{\frac{1 - l o g _{3} ( 2 )}{2}}

True

The solution is

x = 3^{\frac{1 - l o g _{3} ( 2 )}{2}}

lo g_{5} (5^{x} - 20) = 3 - x

2 lo g_{2} (x) = lo g_{2} (x + 12) + 1

v, ln (p) + R ln (v) = C

lo g_{y} (125) = 3

x, ln (x^{2} - y) = 0

What is the answer to log_{3}(2x)=1-log_{3}(x) ?
The answer to log_{3}(2x)=1-log_{3}(x) is x=3^{(1-log_{3}(2))/2}
Solve for x: log_{3}(2x)=1-log_{3}(x)
The solution is x=3^{(1-log_{3}(2))/2}