What is the answer to 600=300log_{10}(t+2) ?

The answer to 600=300log_{10}(t+2) is t=98

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

600=300log_{10}(t+2)

600 = 300 lo g_{10} (t + 2)

t = 98

Solution steps

600 = 300 lo g_{10} (t + 2)

Switch sides

300 lo g_{10} (t + 2) = 600

Divide both sides by

300

lo g_{10} (t + 2) = 2

Apply log rules

t + 2 = 100

Solve

t + 2 = 100 : t = 98

t = 98

Verify Solutions:

t = 98

True

The solution is

t = 98

ln (5 x + 6) = 4

ln (x) = 3.7

lo g_{3} (x^{2} + 7 x + 9) = 2

lo g_{3} (x + 5) + lo g_{3} (x - 7) = 2

lo g_{e} (2 - 3 x) = 0

What is the answer to 600=300log_{10}(t+2) ?
The answer to 600=300log_{10}(t+2) is t=98
Solve for t: 600=300log_{10}(t+2)
The solution is t=98