What is the answer to log_{3}(x+6)+log_{3}(x+4)=1 ?

The answer to log_{3}(x+6)+log_{3}(x+4)=1 is x=-3

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log_{3}(x+6)+log_{3}(x+4)=1

lo g_{3} (x + 6) + lo g_{3} (x + 4) = 1

x = - 3

Solution steps

lo g_{3} (x + 6) + lo g_{3} (x + 4) = 1

Apply log rules

(x + 6) (x + 4) = 3

Solve

(x + 6) (x + 4) = 3 : x = - 3, x = - 7

x = - 3, x = - 7

Verify Solutions:

x = - 3

True

, x = - 7

False

The solution is

x = - 3

6 - 2 ln (x) = 7

lo g_{4} (\frac{x - 2}{2 x + 3}) = 0

lo g_{10} (x) + lo g_{10} (80) = 3

ln (x^{- 1}) = 3

x, ln (x) + ln (x) = 0

What is the answer to log_{3}(x+6)+log_{3}(x+4)=1 ?
The answer to log_{3}(x+6)+log_{3}(x+4)=1 is x=-3
Solve for x: log_{3}(x+6)+log_{3}(x+4)=1
The solution is x=-3