What is the answer to solvefor y,xy=ln(y)+c ?

The answer to solvefor y,xy=ln(y)+c is y=-(\W(-x/(e^c)))/x

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solvefor y,xy=ln(y)+c

solve for

y, x y = ln (y) + c

y = - \frac{W ( - \frac{x}{e ^{c}} )}{x}

Solution steps

x y = ln (y) + c

Switch sides

ln (y) + c = x y

Move

c

to the right side

ln (y) = x y - c

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (y)} = e^{x y - c}

Simplify

e^{l n (y)} : y

y = e^{x y - c}

Solve

y = e^{x y - c} : y = - \frac{W ( - \frac{x}{e ^{c}} )}{x}

y = - \frac{W ( - \frac{x}{e ^{c}} )}{x}

ln (5 x) = - 1

x, 2 x - 1 = e^{l n (x^{2})}

lo g_{2} (4 x) = 5

lo g_{2 x} (16) = lo g_{e} (2 x)

2 lo g_{10} (x) + lo g_{10} (4) = 2

What is the answer to solvefor y,xy=ln(y)+c ?
The answer to solvefor y,xy=ln(y)+c is y=-(\W(-x/(e^c)))/x