What is the answer to solvefor x,2x-1=e^{ln(x^2)} ?

The answer to solvefor x,2x-1=e^{ln(x^2)} is x=1

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solvefor x,2x-1=e^{ln(x^2)}

solve for

x, 2 x - 1 = e^{l n (x^{2})}

x = 1

Solution steps

2 x - 1 = e^{l n (x^{2})}

Apply log rules

2 x - 1 = x^{2}

Solve

2 x - 1 = x^{2} : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{2} (4 x) = 5

lo g_{2 x} (16) = lo g_{e} (2 x)

2 lo g_{10} (x) + lo g_{10} (4) = 2

- 2 ln (x) - 3 = 0

lo g_{2} (2 x + 1) = - 3

What is the answer to solvefor x,2x-1=e^{ln(x^2)} ?
The answer to solvefor x,2x-1=e^{ln(x^2)} is x=1