What is the answer to log_{2}(x^2+x)=1 ?

The answer to log_{2}(x^2+x)=1 is x=1,x=-2

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log_{2}(x^2+x)=1

lo g_{2} (x^{2} + x) = 1

x = 1, x = - 2

Solution steps

lo g_{2} (x^{2} + x) = 1

Apply log rules

x^{2} + x = 2

Solve

x^{2} + x = 2 : x = 1, x = - 2

x = 1, x = - 2

0 = ln (1 + (1 + c^{1}))

lo g_{2} (x - 2) + lo g_{2} (2 x - 1) = 0

lo g_{3} (3 x - 2) - lo g_{3} (x + 2) = 3

6 (ln (4 x) + 1) = 0

ln (5 - 2 x) = 3

What is the answer to log_{2}(x^2+x)=1 ?
The answer to log_{2}(x^2+x)=1 is x=1,x=-2
Solve for x: log_{2}(x^2+x)=1
The solution is x=1,x=-2