What is the answer to solvefor k,pk=-log_{10}(k) ?

The answer to solvefor k,pk=-log_{10}(k) is k=(\W(ln(10)p))/(pln(10))

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solvefor k,pk=-log_{10}(k)

solve for

k, p k = - lo g_{10} (k)

k = \frac{W ( ln ( 10 ) p )}{p ln ( 10 )}

Solution steps

p k = - lo g_{10} (k)

Move

lo g_{10} (k)

to the left side

p k + lo g_{10} (k) = 0

Move

p k

to the right side

lo g_{10} (k) = - p k

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (k)} = 1 0^{- p k}

Simplify

1 0^{l o g_{10} (k)} : k

k = 1 0^{- p k}

Solve

k = 1 0^{- p k} : k = \frac{W ( ln ( 10 ) p )}{p ln ( 10 )}

k = \frac{W ( ln ( 10 ) p )}{p ln ( 10 )}

Verify Solutions:

k = \frac{W ( ln ( 10 ) p )}{p ln ( 10 )}

True

The solution is

k = \frac{W ( ln ( 10 ) p )}{p ln ( 10 )}

lo g_{3} (12 x - 12) = 2 + lo g_{3} (x)

20 = 3 lo g_{2} (1 + x)

lo g_{x + 1} (x^{2} + 2 x - 1) = 2

x, y - 2 = ln (x + e^{2})

lo g_{2} (x) - 3 lo g_{2} (x) = 6

What is the answer to solvefor k,pk=-log_{10}(k) ?
The answer to solvefor k,pk=-log_{10}(k) is k=(\W(ln(10)p))/(pln(10))