What is the answer to log_{3}(x+3)-log_{3}(x+1)=1 ?

The answer to log_{3}(x+3)-log_{3}(x+1)=1 is x=0

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log_{3}(x+3)-log_{3}(x+1)=1

lo g_{3} (x + 3) - lo g_{3} (x + 1) = 1

x = 0

Solution steps

lo g_{3} (x + 3) - lo g_{3} (x + 1) = 1

Add

lo g_{3} (x + 1)

to both sides

lo g_{3} (x + 3) - lo g_{3} (x + 1) + lo g_{3} (x + 1) = 1 + lo g_{3} (x + 1)

Simplify

lo g_{3} (x + 3) = 1 + lo g_{3} (x + 1)

Apply log rules

x + 3 = 3 (x + 1)

Solve

x + 3 = 3 (x + 1) : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

lo g_{3} (x) = 4 lo g_{10} (x) 3

lo g_{x} (10) = \frac{1}{2}

x, lo g_{x} (64) = 2

lo g_{2 x^{2}} (x^{3} + x) = 1

10 = ln (x)

What is the answer to log_{3}(x+3)-log_{3}(x+1)=1 ?
The answer to log_{3}(x+3)-log_{3}(x+1)=1 is x=0
Solve for x: log_{3}(x+3)-log_{3}(x+1)=1
The solution is x=0