What is the answer to log_{3}(2x-2)=log_{3}(x+10) ?

The answer to log_{3}(2x-2)=log_{3}(x+10) is x=12

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log_{3}(2x-2)=log_{3}(x+10)

lo g_{3} (2 x - 2) = lo g_{3} (x + 10)

x = 12

Solution steps

lo g_{3} (2 x - 2) = lo g_{3} (x + 10)

Apply log rules

2 x - 2 = x + 10

Solve

2 x - 2 = x + 10 : x = 12

x = 12

Verify Solutions:

x = 12

True

The solution is

x = 12

lo g_{3} (4 x - 1) = 4

e \cdot ln (x - 10) = e \cdot ln (8)

- 2 lo g_{4} (- 2 x + 3) - 5 = 5

10 lo g_{10} (x) = 36.3

lo g_{10} (2 x - 3) = - 1

What is the answer to log_{3}(2x-2)=log_{3}(x+10) ?
The answer to log_{3}(2x-2)=log_{3}(x+10) is x=12
Solve for x: log_{3}(2x-2)=log_{3}(x+10)
The solution is x=12