What is the answer to log_{3}(4x-1)=4 ?

The answer to log_{3}(4x-1)=4 is x= 41/2

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log_{3}(4x-1)=4

lo g_{3} (4 x - 1) = 4

x = \frac{41}{2}

Solution steps

lo g_{3} (4 x - 1) = 4

Apply log rules

4 x - 1 = 81

Solve

4 x - 1 = 81 : x = \frac{41}{2}

x = \frac{41}{2}

e \cdot ln (x - 10) = e \cdot ln (8)

- 2 lo g_{4} (- 2 x + 3) - 5 = 5

10 lo g_{10} (x) = 36.3

lo g_{10} (2 x - 3) = - 1

2 lo g_{4} (64) = 3 lo g_{4} (x)

What is the answer to log_{3}(4x-1)=4 ?
The answer to log_{3}(4x-1)=4 is x= 41/2
Solve for x: log_{3}(4x-1)=4
The solution is x= 41/2