What is the answer to ln(2x+2)-1=ln(x-1) ?

The answer to ln(2x+2)-1=ln(x-1) is x=(e+2)/(e-2)

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ln(2x+2)-1=ln(x-1)

ln (2 x + 2) - 1 = ln (x - 1)

x = \frac{e + 2}{e - 2}

Decimal Notation

x = 6.56884 \dots

Solution steps

ln (2 x + 2) - 1 = ln (x - 1)

Apply log rules

2 x + 2 = (x - 1) e

Solve

2 x + 2 = (x - 1) e : x = \frac{e + 2}{e - 2}

x = \frac{e + 2}{e - 2}

Verify Solutions:

x = \frac{e + 2}{e - 2}

True

The solution is

x = \frac{e + 2}{e - 2}

ln (x - 2 x^{2}) + ln (4) = 0

lo g_{x^{2}} (x) = lo g_{4} (x)

ln (x + 12) + ln (x - 5) = 2 ln (x)

\frac{1}{2} ln (t - 3) = 0

lo g_{x} (x^{2} + 3 x - 3) = 2

What is the answer to ln(2x+2)-1=ln(x-1) ?
The answer to ln(2x+2)-1=ln(x-1) is x=(e+2)/(e-2)
Solve for x: ln(2x+2)-1=ln(x-1)
The solution is x=(e+2)/(e-2)