What is the answer to log_{10}(3x-2)+log_{10}(x)=0 ?

The answer to log_{10}(3x-2)+log_{10}(x)=0 is x=1

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log_{10}(3x-2)+log_{10}(x)=0

lo g_{10} (3 x - 2) + lo g_{10} (x) = 0

x = 1

Solution steps

lo g_{10} (3 x - 2) + lo g_{10} (x) = 0

Apply log rules

(3 x - 2) x = 1

Solve

(3 x - 2) x = 1 : x = 1, x = - \frac{1}{3}

x = 1, x = - \frac{1}{3}

Verify Solutions:

x = 1

True

, x = - \frac{1}{3}

False

The solution is

x = 1

ln (2 x + 2) - 1 = ln (x - 1)

ln (x - 2 x^{2}) + ln (4) = 0

lo g_{x^{2}} (x) = lo g_{4} (x)

ln (x + 12) + ln (x - 5) = 2 ln (x)

\frac{1}{2} ln (t - 3) = 0

What is the answer to log_{10}(3x-2)+log_{10}(x)=0 ?
The answer to log_{10}(3x-2)+log_{10}(x)=0 is x=1
Solve for x: log_{10}(3x-2)+log_{10}(x)=0
The solution is x=1