What is the answer to ln(x+12)+ln(x-5)=2ln(x) ?

The answer to ln(x+12)+ln(x-5)=2ln(x) is x= 60/7

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ln(x+12)+ln(x-5)=2ln(x)

ln (x + 12) + ln (x - 5) = 2 ln (x)

x = \frac{60}{7}

Solution steps

ln (x + 12) + ln (x - 5) = 2 ln (x)

Apply log rules

(x + 12) (x - 5) = x^{2}

Solve

(x + 12) (x - 5) = x^{2} : x = \frac{60}{7}

x = \frac{60}{7}

Verify Solutions:

x = \frac{60}{7}

True

The solution is

x = \frac{60}{7}

\frac{1}{2} ln (t - 3) = 0

lo g_{x} (x^{2} + 3 x - 3) = 2

ln (ln (\frac{x}{2})) + ln (2) = 1

- lo g_{10} (x) = 12.7

4 = ln (\frac{7}{7 + x})

What is the answer to ln(x+12)+ln(x-5)=2ln(x) ?
The answer to ln(x+12)+ln(x-5)=2ln(x) is x= 60/7
Solve for x: ln(x+12)+ln(x-5)=2ln(x)
The solution is x= 60/7