What is the answer to log_{x}(x^2+3x-3)=2 ?

The answer to log_{x}(x^2+3x-3)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{x}(x^2+3x-3)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{x} (x^{2} + 3 x - 3) = 2

No Solution for x \in R

Solution steps

lo g_{x} (x^{2} + 3 x - 3) = 2

Apply log rules

\frac{ln ( x ^{2} + 3 x - 3 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( x ^{2} + 3 x - 3 )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (x^{2} + 3 x - 3) = 2 ln (x)

Apply log rules

x^{2} + 3 x - 3 = x^{2}

Solve

x^{2} + 3 x - 3 = x^{2} : x = 1

x = 1

Verify Solutions:

x = 1

False

The solution is

No Solution for x \in R

ln (ln (\frac{x}{2})) + ln (2) = 1

- lo g_{10} (x) = 12.7

4 = ln (\frac{7}{7 + x})

lo g_{10} (\frac{1}{x}) = 7.22

5 lo g_{4} (x - 2) - 16 = - 16

What is the answer to log_{x}(x^2+3x-3)=2 ?
The answer to log_{x}(x^2+3x-3)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{x}(x^2+3x-3)=2
The solution is No Solution for x\in\mathbb{R}