What is the answer to log_{2}(x+3)+3=log_{2}(9x+4) ?

The answer to log_{2}(x+3)+3=log_{2}(9x+4) is x=20

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log_{2}(x+3)+3=log_{2}(9x+4)

lo g_{2} (x + 3) + 3 = lo g_{2} (9 x + 4)

x = 20

Solution steps

lo g_{2} (x + 3) + 3 = lo g_{2} (9 x + 4)

Apply log rules

(x + 3) \cdot 8 = 9 x + 4

Solve

(x + 3) \cdot 8 = 9 x + 4 : x = 20

x = 20

Verify Solutions:

x = 20

True

The solution is

x = 20

lo g_{10} (x^{81}) = 4

lo g_{e} (x) = - 1

lo g_{5} (5 x^{2}) - lo g_{5} (4) = 5

ln (x + 2) - ln (x) = 4

lo g_{a} (a) = 2

What is the answer to log_{2}(x+3)+3=log_{2}(9x+4) ?
The answer to log_{2}(x+3)+3=log_{2}(9x+4) is x=20
Solve for x: log_{2}(x+3)+3=log_{2}(9x+4)
The solution is x=20