What is the answer to ln(x^2)=ln(10x)-3 ?

The answer to ln(x^2)=ln(10x)-3 is x=(10)/(e^3)

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ln(x^2)=ln(10x)-3

ln (x^{2}) = ln (10 x) - 3

x = \frac{10}{e ^{3}}

Decimal Notation

x = 0.49787 \dots

Solution steps

ln (x^{2}) = ln (10 x) - 3

Apply log rules

x = \frac{10}{e ^{3}}

Verify Solutions:

x = \frac{10}{e ^{3}}

True

The solution is

x = \frac{10}{e ^{3}}

- 3 = 10 lo g_{10} (\frac{x}{1})

ln (4 x) - 3 ln (x^{2}) = ln (3)

ln (x) + ln (x + 3) = 0

lo g_{10} (x + 5) = lo g_{10} (2 x - 3)

ln (3 x + 3.7) - 1.2 = - 12.3

What is the answer to ln(x^2)=ln(10x)-3 ?
The answer to ln(x^2)=ln(10x)-3 is x=(10)/(e^3)
Solve for x: ln(x^2)=ln(10x)-3
The solution is x=(10)/(e^3)