What is the answer to log_{12}(4x+2)=0 ?

The answer to log_{12}(4x+2)=0 is x=-1/4

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log_{12}(4x+2)=0

lo g_{12} (4 x + 2) = 0

x = - \frac{1}{4}

Decimal Notation

x = - 0.25

Solution steps

lo g_{12} (4 x + 2) = 0

Apply log rules

4 x + 2 = 1

Solve

4 x + 2 = 1 : x = - \frac{1}{4}

x = - \frac{1}{4}

ln (\frac{( x + 3 )}{( x - 1 )}) = 1

lo g_{x} (4) = lo g_{10} (100)

lo g_{5} (x + 5) + lo g_{5} (x - 4) = 3

lo g_{3} (x) = x

lo g_{3} (x) = a

What is the answer to log_{12}(4x+2)=0 ?
The answer to log_{12}(4x+2)=0 is x=-1/4
Solve for x: log_{12}(4x+2)=0
The solution is x=-1/4