What is the answer to ln(x^2)=-8 ?

The answer to ln(x^2)=-8 is x= 1/(e^4),x=-1/(e^4)

Solve for x: ln(x^2)=-8

The solution is x= 1/(e^4),x=-1/(e^4)

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ln (x^{2}) = - 8

x = \frac{1}{e ^{4}}, x = - \frac{1}{e ^{4}}

Decimal Notation

x = 0.01831 \dots, x = - 0.01831 \dots

Solution steps

ln (x^{2}) = - 8

Apply log rules

x^{2} = \frac{1}{e ^{8}}

Solve

x^{2} = \frac{1}{e ^{8}} : x = \frac{1}{e ^{4}}, x = - \frac{1}{e ^{4}}

x = \frac{1}{e ^{4}}, x = - \frac{1}{e ^{4}}

lo g_{2} (x + 9) = lo g_{2} (x - 6) + 4

5^{2} = 25 in lo g_{10} (x)

lo g_{10} (z) + 12 = 9

x, ln (y) = ln (x + 1)

What is the answer to ln(x^2)=-8 ?
The answer to ln(x^2)=-8 is x= 1/(e^4),x=-1/(e^4)
Solve for x: ln(x^2)=-8
The solution is x= 1/(e^4),x=-1/(e^4)