What is the answer to log_{2}(x)+log_{2}(6)=3 ?

The answer to log_{2}(x)+log_{2}(6)=3 is x= 4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x)+log_{2}(6)=3

lo g_{2} (x) + lo g_{2} (6) = 3

x = \frac{4}{3}

Solution steps

lo g_{2} (x) + lo g_{2} (6) = 3

Move

lo g_{2} (6)

to the right side

lo g_{2} (x) = 3 - lo g_{2} (6)

Apply log rules

x = \frac{4}{3}

Verify Solutions:

x = \frac{4}{3}

True

The solution is

x = \frac{4}{3}

lo g_{10} (x) - lo g_{10} (x + 1) = 1

10 = \frac{ln ( 2 )}{ln ( 1 + x )}

ln (x) = 7, ln (\frac{x}{e})

3 ln (x) = ln (x^{3})

lo g_{10} (x) = - 1.9

What is the answer to log_{2}(x)+log_{2}(6)=3 ?
The answer to log_{2}(x)+log_{2}(6)=3 is x= 4/3
Solve for x: log_{2}(x)+log_{2}(6)=3
The solution is x= 4/3