What is the answer to log_{3}(7x)-log_{3}(2)=5 ?

The answer to log_{3}(7x)-log_{3}(2)=5 is x= 486/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(7x)-log_{3}(2)=5

lo g_{3} (7 x) - lo g_{3} (2) = 5

x = \frac{486}{7}

Decimal Notation

x = 69.42857 \dots

Solution steps

lo g_{3} (7 x) - lo g_{3} (2) = 5

Move

lo g_{3} (2)

to the right side

lo g_{3} (7 x) = 5 + lo g_{3} (2)

Apply log rules

7 x = 486

Solve

7 x = 486 : x = \frac{486}{7}

x = \frac{486}{7}

Verify Solutions:

x = \frac{486}{7}

True

The solution is

x = \frac{486}{7}

lo g_{2} (3 - x) + lo g_{2} (- x) = 2

lo g_{b} (9) = - \frac{1}{3}

- lo g_{10} (x) = 2.8

- lo g_{10} (x) = 2.1

ln (5 - 2 x) = - 7

What is the answer to log_{3}(7x)-log_{3}(2)=5 ?
The answer to log_{3}(7x)-log_{3}(2)=5 is x= 486/7
Solve for x: log_{3}(7x)-log_{3}(2)=5
The solution is x= 486/7