What is the answer to solvefor x,log_{10}(-2x)=y ?

The answer to solvefor x,log_{10}(-2x)=y is x=-5^y*2^{y-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,log_{10}(-2x)=y

solve for

x, lo g_{10} (- 2 x) = y

x = - 5^{y} \cdot 2^{y - 1}

Solution steps

lo g_{10} (- 2 x) = y

Apply log rules

- 2 x = 1 0^{y}

Solve

- 2 x = 1 0^{y} : x = - 5^{y} \cdot 2^{y - 1}

x = - 5^{y} \cdot 2^{y - 1}

lo g_{10} (x) + lo g_{10} (x + 4) = 7

2 ln (x) - ln (x + 6) = 3 ln^{2} (x)

4 lo g_{5} (2) = lo g_{5} (x)

lo g_{10} (x) + lo g_{10} (x - 8) = 2

- lo g_{10} (x) = 7.8

What is the answer to solvefor x,log_{10}(-2x)=y ?
The answer to solvefor x,log_{10}(-2x)=y is x=-5^y*2^{y-1}