What is the answer to log_{4}(16)+log_{4}(2x+9)=3 ?

The answer to log_{4}(16)+log_{4}(2x+9)=3 is x=-5/2

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log_{4}(16)+log_{4}(2x+9)=3

lo g_{4} (16) + lo g_{4} (2 x + 9) = 3

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

lo g_{4} (16) + lo g_{4} (2 x + 9) = 3

Move

lo g_{4} (16)

to the right side

lo g_{4} (2 x + 9) = 3 - lo g_{4} (16)

Apply log rules

2 x + 9 = 4

Solve

2 x + 9 = 4 : x = - \frac{5}{2}

x = - \frac{5}{2}

Verify Solutions:

x = - \frac{5}{2}

True

The solution is

x = - \frac{5}{2}

ln (1 + b) = (6.67 \cdot 1 0^{- 4})

\frac{ln ( 2 x - 5 )}{2} = ln (x - 2)

ln (x) \cdot e = 0

ln (7 - 4 x) = 10

lo g_{10} (x^{2}) = 2.0279

What is the answer to log_{4}(16)+log_{4}(2x+9)=3 ?
The answer to log_{4}(16)+log_{4}(2x+9)=3 is x=-5/2
Solve for x: log_{4}(16)+log_{4}(2x+9)=3
The solution is x=-5/2