What is the answer to 4+ln(x)=2.0706 ?

The answer to 4+ln(x)=2.0706 is x= 1/(e^{1.9294)}

Solve for x: 4+ln(x)=2.0706

The solution is x= 1/(e^{1.9294)}

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4 + ln (x) = 2.0706

x = \frac{1}{e ^{1.9294}}

Decimal Notation

x = 0.14523 \dots

Solution steps

4 + ln (x) = 2.0706

Move

4

to the right side

ln (x) = - 1.9294

Apply log rules

x = \frac{1}{e ^{1.9294}}

Verify Solutions:

x = \frac{1}{e ^{1.9294}}

True

The solution is

x = \frac{1}{e ^{1.9294}}

ln (2 x) + ln (3 x) = 15

14 lo g_{10} (x^{2} - x - 6) = 1

2 lo g_{10} (x + 2) = x

4 = 5 lo g_{10} (x) - lo g_{2} (x)

lo g_{2} (x + 1) = - 3

What is the answer to 4+ln(x)=2.0706 ?
The answer to 4+ln(x)=2.0706 is x= 1/(e^{1.9294)}
Solve for x: 4+ln(x)=2.0706
The solution is x= 1/(e^{1.9294)}