What is the answer to -1/2 =log_{10}(x) ?

The answer to -1/2 =log_{10}(x) is x= 1/(sqrt(10))

Solve for x: -1/2 =log_{10}(x)

The solution is x= 1/(sqrt(10))

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- \frac{1}{2} = lo g_{10} (x)

x = \frac{1}{10}

Decimal Notation

x = 0.31622 \dots

Solution steps

- \frac{1}{2} = lo g_{10} (x)

Apply log rules

\frac{1}{10} = x

Switch sides

x = \frac{1}{10}

lo g_{4} (lo g_{4} (2 x)) = 1

lo g_{10} (x - 1) + lo g_{10} (5 x) = 2

50 = 0.5 x + 2 ln (x)

lo g_{6} (- 3 x) + lo g_{6} (- 10 x) = 5

5 + ln (x - 5) = 2

What is the answer to -1/2 =log_{10}(x) ?
The answer to -1/2 =log_{10}(x) is x= 1/(sqrt(10))
Solve for x: -1/2 =log_{10}(x)
The solution is x= 1/(sqrt(10))