What is the answer to solvefor v,w=log_{4}(2v+3) ?

The answer to solvefor v,w=log_{4}(2v+3) is v=(4^w-3)/2

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solvefor v,w=log_{4}(2v+3)

solve for

v, w = lo g_{4} (2 v + 3)

v = \frac{4 ^{w} - 3}{2}

Solution steps

w = lo g_{4} (2 v + 3)

Apply log rules

4^{w} = 2 v + 3

Solve

4^{w} = 2 v + 3 : v = \frac{4 ^{w} - 3}{2}

v = \frac{4 ^{w} - 3}{2}

ln (x^{3} + 2000) = 2

lo g_{2} (4 x) + lo g_{2} (2) = 4

ln (5) = 1 + ln (2 x)

2 ln (x - 1) - ln (x) = 1

x, lo g_{e} (2 x - 1) = - 3

What is the answer to solvefor v,w=log_{4}(2v+3) ?
The answer to solvefor v,w=log_{4}(2v+3) is v=(4^w-3)/2