What is the answer to log_{2}(x+3)+log_{2}(x-3)=0 ?

The answer to log_{2}(x+3)+log_{2}(x-3)=0 is x=sqrt(10)

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log_{2}(x+3)+log_{2}(x-3)=0

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 0

x = 10

Decimal Notation

x = 3.16227 \dots

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 0

Apply log rules

(x + 3) (x - 3) = 1

Solve

(x + 3) (x - 3) = 1 : x = 10, x = - 10

x = 10, x = - 10

Verify Solutions:

x = 10

True

, x = - 10

False

The solution is

x = 10

b, ln (2 b) = 4 ln (4 b)

lo g_{10} (2) + 1 = lo g_{10} (x)

lo g_{2} (x + 3) + lo g_{4} (5 - x) = 3

\frac{5 lo g _{2} ( x - 2 )}{3} = 6

lo g_{2} (x) + lo g_{2} (4 x) = 12

What is the answer to log_{2}(x+3)+log_{2}(x-3)=0 ?
The answer to log_{2}(x+3)+log_{2}(x-3)=0 is x=sqrt(10)
Solve for x: log_{2}(x+3)+log_{2}(x-3)=0
The solution is x=sqrt(10)